for the formation of oxide or sulphide ions has been determining to be endothermic to … This can be understood with the following example of the successive electron affinity of oxygen: O(g) + e- O-(g) EA= -141 kJ. b) oxygen has high electron affinity . 1st Electron Affinity is usually exothermic as the energy released when the nucleus attracts the the additional electron is larger than the energy absorbed to overcome inter-electronic repulsion. a) oxygen is more electronegative . Click here to buy a book, photographic periodic table poster, card deck, or 3D print based on the images you see here! d) O-ion has comparatively larger size than oxygen atom. It is indicated using the symbol Ea and is usually expressed in units of kJ/mol. c) O-ion will tend to resist the addition of another electron . It is applicable to all p-block element groups. Electron affinity is the amount of energy required to detach one electron from a negatively charged ion of an atom or molecule. The electron affinity of oxygen is equal to A. the ionization energy of O-. The second electron affinity (EA 2) is always larger than the first electron affinity (EA 1) as it is hard to add an electron into a negative ion than a neutral atom. B. the ionization energy of O2-. Electron affinity increases from the first element to the second element in a group. Hence, oxygen has lesser electron affinity than that of sulphur and however in a group, it decreases from top to bottom as size increases. Use the Born-Haber cycle and data from Appendix IIB and Table 9.3 in the textbook to calculate the lattice energy of CaO. When an electron is added to a neutral gaseous oxygen atom , the process is exothermic and 141 kJ energy is liberated. C. the second ionization energy of O. D. twice the electron affinity of O+.E. Here are the electron affinities of the 16th and 17th groups. Use this … But in the case of oxygen, the first electron is added to a 2p subshell where one electron is already present. Electron affinity follows a trend on the periodic table. none of these. Therefore spin pair repulsion exists and energy is needed to overcome it ...however the 1st electron affinity of oxygen is still negative. O-(g) + e- O 2-(g) EA= +780 kJ. Calculate the second electron affinity of oxygen using the information below: O^- (g) + e^- ? You may need the following data: electron affinity of oxygen EA_1=-141 kJ/mol, EA_2=744 kJ/mol; ionization energy of calcium IE_1=590 kJ/mol, IE_2=1145 kJ/mol O^2+ (g) EA_2 =? 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